To master Many we ask ‘how many?’ To answer, we count by bundling and stacking to get a total T. Once counted, first a total can be recounted in the same unit to create overload or underload, or to create a different unit; next totals can be added NextTo, or OnTop if the units are the same.

Counting a total T of 7 ones in 3s we get the result T = 7 = 2 3s & 1 = 2B1 3s.

We separate the inside bundles from the outside unbundled singles by a cup becoming a bracket when reporting the result with cup-writing

T = III III I = IIBI = 2B1  3s

Short version: Math Dislike Cured Short

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